In my previous blog I have covered how to UNPIVOT data in HANA, in this blog I am covering how to PIVOT data in HANA.

While converting MS-SQL procedures into HANA procedures, we came across PIVOT statement in one of the select query, unfortunately HANA SQL Script does not support PIVOT operation hence we had to come up with alternative approach. In this blog I will cover two approaches to PIVOT data in HANA

- Using graphical calculation view
- Using HANA SQL Script

**PIVOT Data using Graphical Calculation View:**

**Base Table**: This is a PO header table which has Employee ID, Vendor ID and PO Number.

**PIVOT Output: **In pivot output lets say we want to know how many Purchase Orders placed by each employee, as Excel is the best tool to generate pivot output so I generated below output in excel:

We can get same output using graphical calculation view by following below steps:

- Add a projection node and add base table in it:

- Since there are 6 different employees in base table hence we need to create 6 calculated fields, one corresponding to each employee and these fields will become our pivot column header.
- As we need count of PO for each employee we need to put below formula in each calculated field:

As per above expression, if employee is “E1” then make E1 (new calculated field) = 1 else E1 = 0. Write same expression for all the other fields and change Emp_ID value to E2, E3.., etc.

**Note**: You need to create calculated fields in Projection node and not on Aggregation node otherwise aggregation on calculated fields will not happen.

Here is the output after creating all the calculated fields:

- Connect projection node to Aggregation node and activate the view:

**Pivoted Output:**

In above use case we used **Count** as aggregation function however if you want to use **Sum** or **Max** as aggregated function then you just need to make small change in your calculated field formula and aggregation function in semantic node.

**Changes for Sum: **Lets say you want to check Sum of all POs placed by an employee, I know logically it does not make sense but I think you won’t mind if I take it as an example.

Make above change for all the calculated fields.

**Output:**

**Changes for Max: **

Formula remains the same as Sum but you need to change aggregation function in Semantic node:

**Output:**

**PIVOT Data using HANA SQLScript:**

There are multiple ways of achieving Pivot functionality using HANA SQLScript

**First Option: **

Pivot with Count (replace Count with Sum in case you need Sum as aggregated function)

**Pasting SQL just in case you want to copy:**

select vendor_id, sum(“E1”) AS “E1”, SUM(“E2”) AS “E2”,SUM(“E3”) AS “E3”,SUM(“E4”) AS “E4”,SUM(“E5”) AS “E5”,

SUM(“E6”) AS “E6”

FROM

(

select vendor_id, COUNT(NUM) as “E1”, 0 AS “E2” , 0 AS “E3”, 0 AS “E4”, 0 AS “E5”, 0 AS “E6”

from “ABHISHEAGRAW”.”abhisheagraw::PIVOT_INITIAL_TABLE”

WHERE EMP_ID = ‘E1’ GROUP BY vendor_id

union all

select vendor_id, 0 AS “E1”, COUNT(NUM) as “E2”, 0 AS “E3”, 0 AS “E4”, 0 AS “E5”, 0 AS “E6”

from “ABHISHEAGRAW”.”abhisheagraw::PIVOT_INITIAL_TABLE”

WHERE EMP_ID = ‘E2’ GROUP BY vendor_id

union all

select vendor_id, 0 AS “E1”, 0 as “E2”, COUNT(NUM) AS “E3”, 0 AS “E4”, 0 AS “E5”, 0 AS “E6”

from “ABHISHEAGRAW”.”abhisheagraw::PIVOT_INITIAL_TABLE”

WHERE EMP_ID = ‘E3’ GROUP BY vendor_id

union all

select vendor_id, 0 AS “E1”, 0 as “E2”, 0 AS “E3”, COUNT(NUM) AS “E4”, 0 AS “E5”, 0 AS “E6”

from “ABHISHEAGRAW”.”abhisheagraw::PIVOT_INITIAL_TABLE”

WHERE EMP_ID = ‘E4’ GROUP BY vendor_id

union all

select vendor_id, 0 AS “E1”, 0 as “E2”, 0 AS “E3”, 0 AS “E4”, COUNT(NUM) AS “E5”, 0 AS “E6”

from “ABHISHEAGRAW”.”abhisheagraw::PIVOT_INITIAL_TABLE”

WHERE EMP_ID = ‘E5’ GROUP BY vendor_id

union all

select vendor_id, 0 AS “E1”, 0 as “E2”, 0 AS “E3”, 0 AS “E4”, 0 AS “E5”, COUNT(NUM) AS “E6”

from “ABHISHEAGRAW”.”abhisheagraw::PIVOT_INITIAL_TABLE”

WHERE EMP_ID = ‘E6’ GROUP BY vendor_id

) GROUP BY vendor_id ORDER BY vendor_id

**Second Option: **

Pivot with Count (replace 1 with Num in case you need Sum as aggregated function)

**SQL:**

select vendor_id, sum(“E1”) AS “E1”, SUM(“E2”) AS “E2”,SUM(“E3”) AS “E3”,SUM(“E4”) AS “E4”,SUM(“E5”) AS “E5”,

SUM(“E6”) AS “E6”

FROM

(

select vendor_id, CASE (EMP_ID) WHEN ‘E1’

THEN 1

ELSE 0

END as “E1”,

CASE (EMP_ID) WHEN ‘E2’

THEN 1

ELSE 0

END as “E2”,

CASE (EMP_ID) WHEN ‘E3’

THEN 1

ELSE 0

END as “E3”,

CASE (EMP_ID) WHEN ‘E4’

THEN 1

ELSE 0

END as “E4”,

CASE (EMP_ID) WHEN ‘E5’

THEN 1

ELSE 0

END as “E5”,

CASE (EMP_ID) WHEN ‘E6’

THEN 1

ELSE 0

END as “E6”

from “ABHISHEAGRAW”.”abhisheagraw::PIVOT_INITIAL_TABLE”

)GROUP BY vendor_id ORDER BY vendor_id

Hi Abhishek,

What happens if a new employee is added to the list ? Then we have to restructure the CV and rewrite the script as well, right ?

Regards,

Nithin

This is an important question. I like it and I know now what I should do 🙂

You have got my “like”.

Hi Nithin,

Unfortunately yes, we need to remodel and re-write the script and as far as I know even with PIVOT statement which is available in MS-SQL we need to add these PIVOT fields manually.

Regards,

Abhishek

Hello Abhishek,

Thanks for the informative article. Can we simply transpose the records instead of count or sum . For example:

EMP ID Vendor 1 Vendor2

E1 1000 500

E1 2000 ( blank)

E2 1000 2000

E2 3000 4000

To put it simple, there can be multiple vendors for same employee having different numbers. I need to change it to the column format based on the vendors and add as additional record for the same vendor but with different Number.

Thank you.

Regards,

Prem

Hey Prem,

Can you please paste the expected output?

Abhishek

Hello Abhishek,

The table that I have mentioned in the previous comment is the expected output. Example :

Current table formatEmployee Vendor Value

EMP1 VEND1 100

EMP1 VEND1 200

EMP1 VEND2 300

EMP2 VEND3 400

EMP2 VEND4 500

Expected outputEmployee Vend1 Vend2 Vend3 Vend4

EMP1 100 300 ( Blank) ( Blank )

EMP1 200 ( Blank ) ( Blank ) ( Blank )

EMP2 ( Blank ) ( Blank ) 400 500

I have multiple information in the row format and would like to split it to column format. Can I use the logic that you have explained for this case as well or do you see some challenges implementing?

Thank you.

Regards,

Prem

Hey Prem,

Sorry for delay in response, unfortunately above solution will not work for you, if you try above solution as is you will get output like this which is different from desired o/p. Let me work on this and will get back to you with solution.

Hi Prem,

You can get the expected output if by using self join as shown below

Select

ActualTable.Employee,

Vendor1.Value as Vend1,

Vendor2.Value as Vend2,

Vendor3.Value as Vend3

from Employee as ActualTable

left outer join Employee as Vendor1 on ActualTable.Employee=Vendor1.Employee

and Vendor1.Vendor=’VEND1′

left outer join Employee as Vendor2 on ActualTable.Employee=Vendor2.Employee

and Vendor2.Vendor=’VEND2′

left outer join Employee as Vendor3 on ActualTable.Employee=Vendor3.Employee

and Vendor3.Vendor=’VEND3′

I am also looking for a more performant and elegant approach. However the example shown above also solves the problem.

Thanks

-Anup-

Hello,

Is it possible to Transpose Rows to columns, where as the columns might be dynamic.

Ex: Input

And the output:

The Col2 values might increase dynamically.

Hi Abhishek,

Unfortunately dynamic creation of column is not possible with this approach, we have same limitation in SLQ PIVOT statement as well, columns need to be defined during design time.

Regards,

Abhishek