mn 72 S 1 1 XP + 209 + 72 { 12. (2017 Show that- +xn11. } 4 62 a2 + 62 . Find the cube roots of— 16. 2* + 9 x + 6 - 99.* - 42 25 + 441 26 - 343. 17. a@y-1 + 3 *y–} + 3 xʻy-} + 1. 18. ab (1 + 3 a-$55 + 3 a-{f} + a-18) (ab-1 - 3 afb-1 + 3 at:-} + 1). . CHAPTER IV. SURDS. 12. A surd quantity is one in which the root indicated cannot be denoted without the use of a fractional index. Thus, the following quantities are surds : Ta 4x + Y a + y)} 3/135, Since, from what has been explained in the last chapter, these quantities may be written thus (a + x)* at, (a? + 2?)t, (a + b + c) (oc + it follows that surds may be dealt with exactly as we deal with their equivalent expressions with fractional indices. It is evident that rational quantities may be put in the form of surds, and conversely, expressions which have the form of surds may sometimes be rational quantities. Thus, a = V(a): V(az)3 = Vas; and Ya3 + 3 a2b + 3 ab? + 73 Va + b)$ = a + b. 13. A mixed quantity may be expressed as a surd. Thus, 3 15 = 33. 35 933. 35 = 333 x 5 and so, a my w/x“y. 14. Conversely, a surd may be expressed as a mixed quantity, when the root of any factor can be obtained. Thus, V18 a?l? 19 aʼ62 x 2 a = /Ꮽ ab . 9 apbo. J2 a = 3 ab 12 a. 8/(a + 3^) : anh (a” + b)macy Jay. 15. Fractional surd expressions may be so expressed that the surd portion may be integral. The process is called rationalizing the denominator, and is worth special notice. 121 3 x 7 Ex. 1. _21 72 177 7. It is much easier to find approximately the value of 121, and divide the result by 7, than to find the values of 13 and J7, and divide the former by the latter. ху Ex. 2. Reduce to its simplest form xy |xy(6 c) xy6 (6 c)? 6 с Thus, = = 4 Ex. 3. Find the arithmetical value of 2 73 The denominator is the difference of two quantities, one of hich is a quadratic surd. Now, we know that (2 V3) (2 + 13) 22 - (3) = 4 3 1, and hence we see that by multiplying numerator and denominator by the sum of the quantities in the denominator we can obtain the denominator in a rational form. 4 4 (2 + 13) 4 (2 + /3) 2 13 (2 (3) (2 + 13) 22 (13) 4 (2 + 13) 4 (2 + 13) 4 (2 + 13) 1 14.92820. 4 (472 - 3 13) na so, 472 + 3/3 (4 /3 + 3 /3) (4 /2 - 3 /3) 4(4 12 – 3 13) – 4 (4 72 – 3 13) * (4 2 - 3/3). (4 12)2 – (373) 32 27 We shall now give an example when the surds are not quadratic. Ex 4. Rationalize the denominator of at - y Since (zł)12 (43)12 is (Art. 29, page 175) divisible by act - ył, it follows that the rationalizing factor is their quotient, which is easily found. 16. Surds may be reduced to a common index. Ex. 1. Express mya and /b as surds having a common index. Since ma 16 bă, it follows that, by reducing the fractional indices to a common denominator, the given surds become respectively añ, bmw, or malam, mm/5m. a 1 am, and = 3 (گروه) = تريد Ex. 2. Reduce Nail and Icy to a common index. The least common denominator of the fractional indices of the given surds is 4 x 3 or 12. Hence we proceed as follows:Vasb (a): (ab)Y's "Mab) = ab, (?Y't = "/(*)* = %. When the student has had a little practice, the first two steps of each of the operations may be omitted. 17. Addition and subtraction of similar surds. DEF. Similar surds are those which have the same irrational factors. Ex. 1. Find the sum of V12, 5/27, - 2 175. We have 712 + 5 727 - 2775 122 x 3 + 5 1/32 3 – 2 152 x 3 (2 + 15 - 10) 73 = 7 V3. Ex. 2. Simplify a b + 2ab2 + 63 a-6 2ab2 + 73 a 2ab + 62 a + 2ab + 62 The given expressionvo (a + b)2% 6) (a - b) (a + b)2 6 vā 7 WO a + 6 6 (a + 6)2 (a b)* 4 ab 16 aa 72 18. Multiplication and division of surds. The following examples will best illustrate these operations: a a + 6 a a + 6 a a a = a Ex. 1. Multiply a Vöyz by b Vayu. ab Axty uz aba'y Juz. Ex. 2. Multiply a Vī + cvā by a ✓od. Arranging as in the case of rational quantities, we have a dot on sbd a √6 + ac jd ab sa cd so cd) 1b + a(c - b) Ja Ex. 3. Divide a sb by b Vā. We have, a No. Na 1 Vab. o da b Na. Na 7 When the divisor is a compound quantity it will generally be the best to express the surds as quantities with fractional indices, and proceed as in ordinary division. 19. The square root of a rational quantity cannot be partly rational and partly irrational. If possible, let Va = m + vo; then, squaring, a = m2 + 2m 1b + b; or, 2 m 6 (m + b); (ma + b). a dat b.a a 2 m that is, an irrational quantity is equal to a rational quantity, which is absurd. 20. To find the square root of a binomial, one of whose terms is a quadratic surd. Let a + jo be the binomial. (1); then, squaring, a + 16 = x + y + 2xy,... ... (2). Equating the rational and irrational parts (Art. 19), we |